b^2-28=1-12b^2

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Solution for b^2-28=1-12b^2 equation:


Simplifying
b2 + -28 = 1 + -12b2

Reorder the terms:
-28 + b2 = 1 + -12b2

Solving
-28 + b2 = 1 + -12b2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12b2' to each side of the equation.
-28 + b2 + 12b2 = 1 + -12b2 + 12b2

Combine like terms: b2 + 12b2 = 13b2
-28 + 13b2 = 1 + -12b2 + 12b2

Combine like terms: -12b2 + 12b2 = 0
-28 + 13b2 = 1 + 0
-28 + 13b2 = 1

Add '28' to each side of the equation.
-28 + 28 + 13b2 = 1 + 28

Combine like terms: -28 + 28 = 0
0 + 13b2 = 1 + 28
13b2 = 1 + 28

Combine like terms: 1 + 28 = 29
13b2 = 29

Divide each side by '13'.
b2 = 2.230769231

Simplifying
b2 = 2.230769231

Take the square root of each side:
b = {-1.493575988, 1.493575988}

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